podstawy trapezu mają 6 cm i 10cm, a wysokość5 cm . oblicz pole tego trapezu
P=(6+10)*5/2
P=16*5/2=8*5=40
P= 1/2(a+b)xh
a=6cm
b=10cm
h=5cm
P= 1/2(10cm+6cm)x5cm
P=8cmx5cm = 40cm2
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P=(6+10)*5/2
P=16*5/2=8*5=40
P= 1/2(a+b)xh
a=6cm
b=10cm
h=5cm
P= 1/2(10cm+6cm)x5cm
P=8cmx5cm = 40cm2