Odpowiedź:
a)
a=180°-50°=130°
b=180°-123°=57°
&=40°
y=180°-40°=140°
b)
a=180°-90°-65°=25°
y=180°-140°=40°
B=180°-140°-20°=20°
&=60° kat wierzcholkowy
Zad 1
alfa = 180 - 50 = 130
beta = 180 - 123 = 57
gamma = 180 - 40 = 140 delta = 40
alfa = 180 - ( 65 + 90 ) = 25
gamma = 180 - 140 = 40 beta = 40 - 20 = 20
delta = 180 - ( 50 + 70 ) = 60
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Odpowiedź:
a)
a=180°-50°=130°
b=180°-123°=57°
&=40°
y=180°-40°=140°
b)
a=180°-90°-65°=25°
y=180°-140°=40°
B=180°-140°-20°=20°
&=60° kat wierzcholkowy
Odpowiedź:
Zad 1
a)
alfa = 180 - 50 = 130
beta = 180 - 123 = 57
gamma = 180 - 40 = 140 delta = 40
b)
alfa = 180 - ( 65 + 90 ) = 25
gamma = 180 - 140 = 40 beta = 40 - 20 = 20
delta = 180 - ( 50 + 70 ) = 60