Podane wyrażenie doprowadź do najprostszej postaci.
a) (x+y)2 - (x-y)2 =
b) (x+2y)2 +(x+y) (2x+2y) =
c) (3x-4)2 + (4x-5)2 =
d) (3x-4)2 - (4x-5)2 =
e) (3+4x)2 - (1-2x)2 =
to 2 to jest kwadrat jak cos....czyli ze wyrazenie w nawiasie do kwadratu :)
prosze o pomoc ;]
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a) (x+y)² - (x-y)² =x²+2xy+y²-x²+2xy-y²=4xy
b) (x+2y)² +(x+y) (2x+2y) =x²+4xy+4y²+2x²+4xy+2y²=3x²+6y²+8xy
c) (3x-4)² + (4x-5)² =9x²-24x+16+16x²-40x+25=25x²-64x+41
d) (3x-4)² - (4x-5)² =9x²-24x+16-16x²+40x-25=-7x²+16x-9
e) (3+4x)² - (1-2x)² =9+24x+16x²-1+4x-4x²=12x²+28x+8