Question

Podane kwadraty przedstaw w postaci sum:
a) (c+⅓)²
b) (√2+4b)²
c) (4√3y+√12)²
d) (a²+2b³)²

Answer 1

A) (c+⅓)²=(c+⅓)*(c+⅓)=c²+⅔c+1/9
b) (√2+4b)²=(√2)²+2*√2*4b+(4b)²=2+8√2*b+16b²
c) (4√3y+√12)²=(4√3y)²+2*(4√3y)*√12+(√12)²=
48y²+8√36y+12=48y²+48y+12

d) (a²+2b³)²=(a²)²+2*a²*2b³+(2b³)²=
a⁴+4a²b³+4b⁶