podaj pole prostokąta o obwodzie równym 2x+6y jesli jeden bok ma długość 3y-x
O = 2x+6y
O = 2(x+3y)
O = 2(a+b)
a+b = x+3y
a = x+3y-b
b = 3y-x
a = x+3y-(3y-x) = x+3y-3y+x = 2x
a = 2x
P = ab
P = 2x(3y-x) = 6xy-2x² = 2x(3y-x)
P = 2x(3y-x) [j²]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
O = 2x+6y
O = 2(x+3y)
O = 2(a+b)
a+b = x+3y
a = x+3y-b
b = 3y-x
a = x+3y-(3y-x) = x+3y-3y+x = 2x
a = 2x
b = 3y-x
P = ab
P = 2x(3y-x) = 6xy-2x² = 2x(3y-x)
P = 2x(3y-x) [j²]