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a²+2ab+b²=(a+b)²
16x²+16x+4=(4x)²+2·4x·2+2²=(4x+2)²
√(a²)=|a|
√(16x²+16x+4)=√[(4x+2)²]=|4x+2|
f(x)=|2x+1|+|4x+2|-2
m zerowe
f(x)=0
|2x+1|+|4x+2|-2=0
|2x+1|+2|2x+1|-2=0
3|2x+1|=2/:3
|2x+1|=2/3
2x+1=2/3 v 2x+1= -2/3
2x=- 1/3 v 2x= -1 2/3= -5/3
x=-1/6 v x= -5/6