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v=24km/h=24*1000m/3600s=6,67 m/s
a=v/t
a=6.67m.s/10s=0,6 m/s2
v=24km/h=6⅔ m/s a=v/t
t=10s
a=(6⅔ m/s)/10s=⅔ m/s²
średnie przyspieszenie pociągu wynosi ⅔ m/s²