Question

Plz bantu jawab nomer 11 yhaaa

Answer 1

∫ 3x/ [3x² + 1]² dx = 

Misalkan 3x² + 1 = u ⇒ 6x dx = du, maka

∫ 3x/ [3x² + 1]² dx = 1/2 .∫ 6x dx/ [3x² + 1]² =

1/2 .∫ 6x dx/ [3x² + 1]² = 1/2 .∫ du/ u² =

1/2 .∫ u⁻² du = 1/2. 1/[-2+1] u⁻¹ + C =

-1/2 . 1/[3x² + 1] + C =




∴ ∫ 3x/ [3x² + 1]² dx =