Odpowiedź:
a. (4x^2+4xy-7)+(2x^2-3xy)=4x^2+4xy-7+2x^2-3xy=
=6x^2+xy-7
b. (5x^2-4x+3)-(5x^2-5x-7)=5x^2-4x+3-5x^2+5x+7=
=10+x
c. (12ab-7a+6b+1)-(6ab-6a+6b)=
=12ab-7a+6b+1-6ab+6a-6b=6ab-a+1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
a. (4x^2+4xy-7)+(2x^2-3xy)=4x^2+4xy-7+2x^2-3xy=
=6x^2+xy-7
b. (5x^2-4x+3)-(5x^2-5x-7)=5x^2-4x+3-5x^2+5x+7=
=10+x
c. (12ab-7a+6b+1)-(6ab-6a+6b)=
=12ab-7a+6b+1-6ab+6a-6b=6ab-a+1