Question

Plis tolong bantu donk soal nya besok di kumpul :)
prisma segi n) ( diagonal bidang ) ( bidang diagonal ) (diagonal ruang)
n = 3 ( diagonal bidang ) ( bidang diagonal ) ( diagonal ruang )
n = 4 ( diagonal bidang ) ( bidang diagonal) ( diagonal ruang )
n = 5 ( diagonal bidang ) ( bidang diagonal ) ( diagonal ruang )
n = p ( diagonal bidang ) ( bidang diagonal ) ( diagonal ruang )
buat cara nya ya !

Answer 1

Diagonal sisi/bidang = n(n-1)
* p(p - 1)
* 3(3-1) = 6
* 4(4-1) = 12
* 5(5-1) = 20
Bidang Diagonal = (n(n-1))/2
* (p(p - 3))/2
* (3(3-3))/2 = -
* (4(4-3))/2 = 2
* (5(5-3))/2 = 5
Diagonal ruang = n(n-3)
* p(p - 3)
* 3(3-3) = 0
* 4(4-3) = 4
* 5(5-3) = 10

semoga membantu:)