mA = 2 kg
mB = 1 kg
vA = v
vB = - 6 m/s
vA' = - 3 m/s
vB' = 8 m/s
vA = ?
Jawab
Hk kekekalan momentum
mA.vA + mB.vB = mA.vA' + mB.vB'
2.v + 1.(-6) = 2.(-3) + 1 . 8
2.v - 6 = - 6 + 8
2.v = 8
v = 4 m/s
Kecepatan bola A sebelum tumbukan 4 m/s.
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mA = 2 kg
mB = 1 kg
vA = v
vB = - 6 m/s
vA' = - 3 m/s
vB' = 8 m/s
vA = ?
Jawab
Hk kekekalan momentum
mA.vA + mB.vB = mA.vA' + mB.vB'
2.v + 1.(-6) = 2.(-3) + 1 . 8
2.v - 6 = - 6 + 8
2.v = 8
v = 4 m/s
Kecepatan bola A sebelum tumbukan 4 m/s.