logaritma
(³log (⁵log 125) ) / (²log (¹⁰log 10)) = p/q
p = ³log (⁵log 125) = ³log ( ⁵log 5³)= ³log (3) = 1
q = ²log (¹⁰log 10) = ²log (1) = 0
p/q = 1/0 = ~
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Verified answer
logaritma
(³log (⁵log 125) ) / (²log (¹⁰log 10)) = p/q
p = ³log (⁵log 125) = ³log ( ⁵log 5³)= ³log (3) = 1
q = ²log (¹⁰log 10) = ²log (1) = 0
p/q = 1/0 = ~