9.
F - μk.m.g.cos 53 - m.g.sin 53 = m.a
F - 1/3. 20. 10. 3/5 - 20. 10. 4/5 = 20. 3
F - 40 - 160 = 60
F = 260 N
Jawaban. A
10.
Gaya gesekan
f = μs.m.g.cos 30
f = 0,9. 2. 10. 1/2. √3
f = 9√3 N
Jawaban. C
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9.
F - μk.m.g.cos 53 - m.g.sin 53 = m.a
F - 1/3. 20. 10. 3/5 - 20. 10. 4/5 = 20. 3
F - 40 - 160 = 60
F = 260 N
Jawaban. A
10.
Gaya gesekan
f = μs.m.g.cos 30
f = 0,9. 2. 10. 1/2. √3
f = 9√3 N
Jawaban. C