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pH = - log [H+]
[H+] = 10⁻⁵
[H+] = Ka x mol asam/mol garam
10⁻⁵ = 10⁻⁵ x (0,2x0,1) / mol garam
mol garam = 0,02 mol
massa = 0,02 mol x 82 gr/mol = 1,64 gr => jawabannya(B)
9. hidrolisis sebagian dan bersifat asam garam dari basa lemah dan asam kuat
jawabannya (C)
10. M NaCN = 2,45 gr / 49 gr/mol x 1000/500 = 0,1 M
[OH-] = √kw/ka x M
[OH-] = √10⁻¹⁴/7x10⁻¹⁰ x 0,1
[OH-] = 1/7¹/² x10⁻²·⁵
pOH = - log 1/7¹/² x10⁻²·⁵
pOH = 2,5 - log 1/7¹/²
pH = 14 - pOH
pH = 14 - (2,5 - log 1/7¹/² )
pH = 11,5 + log 1/7¹/²
pH = 11,5 + 1/2 log 1/7