4N03L
Ρl = 1,5 g/cm3 ρo = 0,9 g/cm3 ρo x Vo = ρl x Vol Vol = (ρo x Vo) / ρl Vol = (ρo / ρl) x Vo Vol = (0,9 x 1,5) x Vo Vol = 0,6 Vo = 60% Vo percentage of the object on the surface of liquid is ... 100 % - 60% = 40 %
Answer is B. 40 %
ρl = density of liquid ρo = density of object Vo = volume of object Vol = volume object in liquid
ρo = 0,9 g/cm3
ρo x Vo = ρl x Vol
Vol = (ρo x Vo) / ρl
Vol = (ρo / ρl) x Vo
Vol = (0,9 x 1,5) x Vo
Vol = 0,6 Vo = 60% Vo
percentage of the object on the surface of liquid is ...
100 % - 60% = 40 %
Answer is B. 40 %
ρl = density of liquid
ρo = density of object
Vo = volume of object
Vol = volume object in liquid