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Verified answer
Kelas 8 MatematikaBab Persamaan Garis
(6, 0) dan (0, -4)
m1 = (y2 - y1)/(x2 - x1)
m1 = (-4 - 0)/(0 - 6)
m1 = -4/-6
m1 = 2/3
m1 . m2 = -1
2/3 . m2 = -1
m2 = -1 . 3/2
m2 = -3/2
y - y1 = m (x - x1)
y - 0 = (-3/2) . (x - 6)
2y = -3x + 18
3x + 2y - 18 = 0