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jumlah getaran(n)=6
waktu(t)=1,5s
ditanyakan:
frekuensi(f)=?
periode(T)=?
cepat rambat(v)=?
jawab:
f=n/t
f=6/1,5
f=4Hz
T=t/n
T=1,5/6
T=0,25s
3lambda=90cm
lambda=90/3
lambda=30cm
v=lambda×f
v=30cm×4Hz
v=120cm/s
jadi,f=4Hz T=0,25s v=120cm/s
jawabannya B
10.diketahui:
cepat rambat(v)=340m/s
t1=3s
t2=4s
ditanyakan:
jarak antara 2 tebing(s)
jadi, jawabannya C. 1.190m