PILNIE POTRZEBUJE POMOCY!! zadania w załącznikach!!!ZADANIA:6.26 - b,d, f, h6.27-b,d,f6.28- b,d6.30-.... Question from @Himmel

December 2018 1 20 Report

PILNIE POTRZEBUJE POMOCY!! zadania w załącznikach!!!
ZADANIA:
6.26 - b,d, f, h
6.27-b,d,f
6.28- b,d
6.30-a,c,e
6.33-a,c,e
!!!!

molik95 6.26
b) 1 - $\frac{4}{x+5}$
x+5≠0
x≠-5
1 - $\frac{4}{x+5}$ = $\frac{x+5}{x+5}$ - $\frac{4}{x+5}$ = $\frac{x+1}{x+5}$

d) $\frac{3}{4} - \frac{2}{x+1}$
x+1≠0
x≠-1
$\frac{3}{4} - \frac{2}{x+1}$ = $\frac{3x+3}{4x+4} - \frac{8}{4x+4}$ = $\frac{3x-5}{4x+4}$
f) 0,1 - $\frac{3}{x+1}$
x+1≠0
x≠-1
0,1 - $\frac{3}{x+1}$ = $\frac{1}{10}$ - $\frac{3}{x+1}$ = x+1/10x+10
- 30/10x+10 = x-29/ 10x+10
h) $\frac{3}{x+4}$ - 0,25
x+4≠0
x≠-4
$\frac{3}{x+4}$ - 0,25 = $\frac{3}{x+4}$ - $\frac{1}{4}$ = $\frac{12}{4x+16}$ - $\frac{x+4}{4x+16}$ = $\frac{8-x}{4x+16}$

6.27
b) $\frac{3}{x-3} + \frac{4+x}{x}$
x≠0 x-3≠0
x≠0 x≠3
$\frac{3}{x-3} + \frac{4+x}{x}$ = $\frac{3x}{x(x-3)} + \frac{(4+x)(x-3)}{x(x-3)}$ = $\frac{3x}{x(x-3)} +\frac{4x+ x^{2} - 3x -12}{x(x-3)}$ = $\frac{3x}{x(x-3)} + frac{x^{2}+x-12}{x(x-3)}$ = $\frac{x^{2} +4x -12}{x(x-3)}$ = $\frac{(x-2)(x+2)}{x(x-3)}$
$x^{2} +4x-12$ =0
Δ= 16-4*1*(-12)=16+ 48=64
√Δ=8
x1=-4-8/2= -4/2 =-2 x2= -4+8/2 = 4/2=2
d) $\frac{x+1}{3x+1} - \frac{2}{2-x}$
3x+1≠0 2-x≠0
3x≠-1 -x≠-2
x≠-1/3 x≠2
$\frac{x+1}{3x+1} - \frac{2}{2-x}$ = $\frac{(x+1)(2-x)}{(3x+1)(2-x)} - \frac{2(3x+1)}{(3x+1)(2-x)}$ = $\frac{(x+1)(2-x)- 6x-2}{(3x+1)(2-x)}$ = $\frac{2x- x^{2} +2 -x - 6x-2}{(3x+1)(2-x)}$ = $\frac{-5x-x^{2}}{(3x+1)(2-x)}$ = $\frac{x(-x-5)}{(3x+1)(2-x)}$
f) $\frac{x}{x-1} - \frac{2x+3}{2x}$
x-1≠0 2x≠0
x≠1 x≠0
$\frac{x}{x-1} - \frac{2x+3}{2x}$ = $\frac{ 2x^{2} }{2x(x-1)} - \frac{(2x+3)(x-1)}{2x(x-1)}$ = $\frac{2 x^{2} }{2x(x-1)} - \frac{2 x^{2} -2x+3x-3}{2x(x-1)}$ = $\frac{2 x^{2}- 2 x^{2} -x+3 }{2x(x-1)}$ = $\frac{ -x+3 }{2x(x-1)}$

6.28
b) $\frac{x-2}{x-3} - \frac{x-1}{x+3}$
x-3≠0 x+3≠0
x≠3 x≠-3
$\frac{x-2}{x-3} - \frac{x-1}{x+3}$ = $\frac{(x-2)(x+3)}{(x-3)(x+3)} - \frac{(x-1)(x-3)}{(x+3)(x-3)}$ = $\frac{( x^{2}-2x+3x - 6)}{(x-3)(x+3)} - \frac{( x^{2}-3x-x+3)}{(x+3)(x-3)}$ = $\frac{(x^{2}+x - 6 - x^{2}+4x-3)}{(x-3)(x+3)}$ = $\frac{(5x-9)}{(x-3)(x+3)}$
d) $\frac{x-1}{3x-6} - \frac{x+1}{3x+6}$
3x-6≠0 3x+6≠0
3x≠6 3x≠-6
x≠2 x≠-2
$\frac{x-1}{3x-6} - \frac{x+1}{3x+6}$ = $\frac{(x-1)(3x+6)}{(3x-6)(3x+6)} - \frac{(x+1)(3x-6)}{(3x+6)(3x-6)}$ = $\frac{(3 x^{2} +6x-3x-6)}{(3x-6)(3x+6)} - \frac{ 3x^{2}-6x+3x-6}{(3x+6)(3x-6)}$ = $\frac{(3 x^{2} +3x-6)}{(3x-6)(3x+6)} - \frac{ 3x^{2} -3x-6}{(3x+6)(3x-6)}$ = $\frac{(3 x^{2} +3x-6- 3x^{2} +3x+6)}{(3x-6)(3x+6)}$ = $\frac{6x}{(3x-6)(3x+6)}$

reszta rozwiązan w załączniku

2 votes Thanks 1

Que paso con las espresas de hierro y carbon durante la revolucion industrial?

Que es mas facil de predecir en el clima. Un huracan o un tornado?

Recommend Questions

Life Enjoy

Get in touch

Social