Pilnie potrzebuję pomocy!!!!! Mam napisać trzy typy spalania dla butanu i pentanu. Z góry dziękuję za pomoc.
C5H12+8O2...>5CO2+6H2O-PENTAN
C5H12+11/2 O2----->5CO+6H2O-PENTAN
C5H12+3O2---->5C+6H2O-PENTAN
2C4H10+13O2--->8CO2+10H2O-BUTAN
2C4H10+9O2--->8CO+10H2O-BUTAN
2C4H10+5O2---->8C+10H2O
POZDRO
butan - C₄H₁₀
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O <-spalanie całkowite
2C₄H₁₀ + 9O₂ -> 8CO + 10H₂O <-półspalanie
2C₄H₁₀ + 5O₂ -> 8C +10H₂O <-spalanie niecałkowite
pentan - C₅H₁₂
C₅H₁₂ + 8O₂ -> 5CO₂ + 6H₂O
2C₅H₁₂ + 11O₂ -> 10CO + 12H₂O
C₅H₁₂ + 3O₂ -> 5C + 6H₂O
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C5H12+8O2...>5CO2+6H2O-PENTAN
C5H12+11/2 O2----->5CO+6H2O-PENTAN
C5H12+3O2---->5C+6H2O-PENTAN
2C4H10+13O2--->8CO2+10H2O-BUTAN
2C4H10+9O2--->8CO+10H2O-BUTAN
2C4H10+5O2---->8C+10H2O
POZDRO
butan - C₄H₁₀
2C₄H₁₀ + 13O₂ -> 8CO₂ + 10H₂O <-spalanie całkowite
2C₄H₁₀ + 9O₂ -> 8CO + 10H₂O <-półspalanie
2C₄H₁₀ + 5O₂ -> 8C +10H₂O <-spalanie niecałkowite
pentan - C₅H₁₂
C₅H₁₂ + 8O₂ -> 5CO₂ + 6H₂O
2C₅H₁₂ + 11O₂ -> 10CO + 12H₂O
C₅H₁₂ + 3O₂ -> 5C + 6H₂O