Question

PILNE!!!

Oblicz pole trójkąta o wymiarach

a=√7

h=4√2

Answer 1

P=½ah

P=½*√7*4√2=√7*√8=√56=2√14

Answer 2

\sqrt{7}x4\sqrt{2}:2=\sqrt{7}x2\sqrt{2}=\sqrt{7}x\sqrt{8}=\sqrt{56}=2\sqrt{14}