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bo
(2 *3)+(4*2√2)+(2*4√2) = 6+8√2 +8√2 = 6 + 16√2
c=√17
(√17)*3+3+(2√2)*4= 3√17+3+8√2=12√1+8√2+3
Odp.: Suma tych krawędzi to (12√1+8√2+3).