PILNE !!!!Ile molo NaOH potrzeba do przygotowania
a)250 g roztworu o stężeniu 6%
b)200g roztw.o stęż. 5%
Odp.
ms=(Cp*mr)/100[%];
a) ms=(250[g]*6[%])/100[%]=15[g]
M(NaOH)=23[g/mol]+17[g/mol]=40[g/mol].
1[mol] NaOH -40[g] NaOH;
x[moli] NaOH - 15[g] NaOH;
x=15/40=0,375[mola] NaOH.
b) ms=(Cp*mr)/100[%];
ms=(200[g]*5[%])/100[%]=10[g] NaOH.
x [moli] NaOH - 10[g] NaOH.
x=10/40=0,25[mola] NaOH.
Odp. a) 0,375[mola] NaOH; b) 0,25[mola] NaOH
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Odp.
ms=(Cp*mr)/100[%];
a) ms=(250[g]*6[%])/100[%]=15[g]
M(NaOH)=23[g/mol]+17[g/mol]=40[g/mol].
1[mol] NaOH -40[g] NaOH;
x[moli] NaOH - 15[g] NaOH;
x=15/40=0,375[mola] NaOH.
b) ms=(Cp*mr)/100[%];
ms=(200[g]*5[%])/100[%]=10[g] NaOH.
1[mol] NaOH -40[g] NaOH;
x [moli] NaOH - 10[g] NaOH.
x=10/40=0,25[mola] NaOH.
Odp. a) 0,375[mola] NaOH; b) 0,25[mola] NaOH