Pierwszy wyraz ciągu geometrycznego wynosi 1 zaś czwarty wynosi 64. Ile wynosi iloraz tego ciągu?
an=a1*q do potegi n-1 a4=1*q do potegi4-1 64=1*q do potegi 3 q do potegi 3=64 q=4
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an=a1*q do potegi n-1 a4=1*q do potegi4-1 64=1*q do potegi 3 q do potegi 3=64 q=4