Question

pierwiastki

matematyka z plusem

1 gim.

Answer 1

b)12-(√144)²×3/-(√81)²=12-144×3/-81=12-432/-81=-420/-81=5 5/27

d)-√100-3×(√25)²/√0,0001=-10-3×25/0,01=-10-75/0,01=-85/0,01=-8500

 

a)³√8000=20, ³√27000=30, ³√216=6, ³√343=7, ³√729=9

b)³√8/125=2/5, ³√27/64=3/4, ³√512/1000=8/10, ³√125/1000000=5/100, ³√64/8000=4/20

c)³√0,001=0,1, ³√0,008=0,2, ³√0,125=0,5, ³√0,064=0,4, ³√0,000027=0,03

 

a)(√4/9)²-(√64/81)²=4/9-64/81=38/81-64/81=-26/81

c)(√1 7/9)²+(√81)²=1 7/9+81=82 7/9