November 2018 1 31 Report

wyznacz dziedzine funkcji i miejsce zerowe:

f(x)=x(x2-9)/ x (x+3)

f(x)=x2-2x+1/ x2-4x+4

f(x)=x2+3x/ x2+6x+9

f(x)= 1+1/x/ pierwiastek z x+3


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