( pierwiastek z 3 - pierwiastek z 12 + pierwiastek z 27) * pierwiastek z 3.... Question from @joro

September 2018 2 15 Report

( pierwiastek z 3 - pierwiastek z 12 + pierwiastek z 27) * pierwiastek z 3

123bodzio

(√3 - √12 + √27)*√3 = (√3 - 2√3 + 3√3) * √3 = 2√3 * √3 = 2 * 3 = 6

6 votes Thanks 2

D4m13n

$(\sqrt3 - \sqrt12 + \sqrt27) * \sqrt3 = x$

$\sqrt9 - \sqrt36 + \sqrt81 = x$

3 - 6 + 9 = x

x = 6

3 votes Thanks 4

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