September 2018 1 15 Report

2^{2,5} : 16^{1/2} =

2^{0,2} * \sqrt[5]{4} =

pierwiastek stopnia 3 z pierwiastka 8 * pierwiastek z pierwiastka 3 stopnia z 16 =

1

____

\sqrt[3]{5}^{4} * \sqrt{25}^{3} =


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