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k+a=1200
5a+a=1200
6a=1200
a=200 - aut
k=10000 - kół
auta y
x+y=1200
5y+y=1200
6y=1200
y=1200/6
y=200
x=5y=5*200=1000
koła x=1000
auta y=200
Odp.
Na parkingu było 200 aut i 1000 kół/
pozdrawiam:)