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a)
O = 8π
8π = 2πr
r = 4cm
O = 1,2π
1,2π= 2πr
r = 0,6cm = 6mm
b)
średnica d = 2r (dwóm długościom promienia r)
O = 3π
3π= 2πr
r = 3/2 cm czyli d = 2*3/2 = 3 cm
O = 8,6π
2πr = 8,6π
r = 4,3 -----------średnica 8,6 cm