Penjelasan dengan langkah-langkah:
Jawaban ada pada lampiran
Mata pelajaran : Matematika
kelas : 10
materi : Trigonometri
kode soal : 2
kode kategorisasi :10.27
Trigonometri
•
sin 15° cos 15°
= 1/2 sin 2(15°)
= 1/2 × 1/2
= 1/4 ✔
- (cos 5π/12 + cos π/12)
= - 2 cos (5π/12 + π/12)/2 cos (5π/12 - π/12)/2
= -2 cos π/4 cos π/6
= -2 × 1/2 √2 × 1/2 √3
= - 1/2 √6
3 sin 75° cos 15°
= 3/2 × 2 sin 75° cos 15°
= 3/2 (sin (75 + 15) + sin (75 - 15))
= 3/2 (1 + 1/2 √3)
= 3/4 (2 + √3)
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Penjelasan dengan langkah-langkah:
Jawaban ada pada lampiran
Detail jawaban
Mata pelajaran : Matematika
kelas : 10
materi : Trigonometri
kode soal : 2
kode kategorisasi :10.27
Trigonometri
•
sin 15° cos 15°
= 1/2 sin 2(15°)
= 1/2 × 1/2
= 1/4 ✔
•
- (cos 5π/12 + cos π/12)
= - 2 cos (5π/12 + π/12)/2 cos (5π/12 - π/12)/2
= -2 cos π/4 cos π/6
= -2 × 1/2 √2 × 1/2 √3
= - 1/2 √6
•
3 sin 75° cos 15°
= 3/2 × 2 sin 75° cos 15°
= 3/2 (sin (75 + 15) + sin (75 - 15))
= 3/2 (1 + 1/2 √3)
= 3/4 (2 + √3)