Question

Pertanyaan di gambar berikut:

Answer 1

f(x)=(3x-2)/(4x+3)

g(x)=2x+1

fog(x) = f(g(x)) (g dimasukin ke f)

f(g(x))=(3(2x+1)-2)/(4(2x+1)+3)

f(g(x))=(6x+3-2)/(8x+4+3)

f(g(x))=(6x+1)/(8x+7)

fog(x) = y = (6x+1)/(8x+7)

diinvers, maka

fog-1(x):

x = (6y+1)/(8y+7)

x(8y+7) = 6y+1

8xy+7x = 6y+1

8xy-6y = 1 - 7x

y(8x-6) = (1-7x)

y = (1-7x) / (8x-6)

fog-1(x) = (1-7x) / (8x-6)

fog-1(4) = (1-7(4)) / (8(4)-6)

= (1-28) / (32-6)

= -27/26