Persamaan kuadrat 2x^2 + mx - (m+1) = 0 mempunyai akar-akar p dan q. jika p^2.q + p.q^2 = 3 maka nilai m ....
THN
2x^2+mx-(m+1), p+q=-b/a=-m/2, p.q=c/a=-(m+1)/2, p^2q+pq^2=3, pq(p+q)=3, -(m+1)/2.m/2=3, (m^2+m)/4=3, m^2+m=12, m^2+m-12=0, (m+4)(m-3)=0, m=-4 atau m=3
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noviantikidrau
terimakasih ^^
