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karna tegak lurus, m1 = -1/m2 ----> m1 = -1/3/2 = -2/3
Persamaan garis melalui (6, -2)
(y - y1 ) = m ( x - x1 )
( y + 2 ) = -2/3 ( x - 6 ) ---> x 3
3 ( y + 2 ) = -2 ( x - 6 )
3y + 6 = -x + 12
x + 3y -12 + 6 = 0
x + 3y - 6 = 0