Question

Persamaan garis yang tegak lurus dengan garis 3y + 2x = 0 dan melalui titik (-3,5) adalah

Answer 1

M = -a/b
m = -2/3
m2 = 3/2
m2x + c = y
3/2(-3) + c = 5
-9/2 + c = 5/1
c = 5/1 + 9/2
c = 10/2 + 9/2
c = 19/2

y = 3/2x + 19/2
atau
3x + 2y + 19 = 0

Answer 2

3y + 2x = 0
3y + 2x - 2x = 0 -2x
3y = -2x
3y/3 = -2x/3
y = -2/3x
m = -2/3
m(x-x1) = y - y1
-2/3 (x-(-3)) = y -5
-2/3x -6/3 = y - 5
-2/3x.3 - 6/3.3 = y.3 -5.3
-2x -6 = 3y -15
-2x -6 -3y + 15 = 3y -3y +15 - 15
-2x -3y -6 + 15 = 0
-2x -3y +9 = 0