Perbandingan panjang, lebar, dan tinggi suatu balok adalah 3:2:1. Jika luas permukaan balok tersebut adalah 88cm, tentukan ukuran balok tersebut !
BryanLaurentio
Luas permukaan = 2(pl pt lt) 88= 2 (3x2x . 3x 1x. 2x 1x) 88= 2(6x+3x+2x) 88=12x+6x+4x 88= 22x 88/22= x 4=x
panjang 3.4= 12 cm lebar =2.4 = 8cm tinggi = 1.4 = 4 cm Semoga membantu
2 votes Thanks 10
marfaaudilla19DIT = PANJANG = 3 LEBAR = 2 TINGGI = 1 DIK = LUAS PERMUKAAN PERBANDINGAN = ( 3 X 2 ) + ( 2 X 1 ) + ( 3 X 1 ) X 2 = 22 SOL = 88 CM PANJANG = DIT/DIK X SOL = 3/22 X 88 = 12 : 2 = 6 LEBAR = DIT/DIK X SOL = 2/22 X 88 = 8 : 2 = 4 TINGGI = DIT/DIK X SOL = 1/22 X 88 = 4 : 2 = 2 KET = DIBAGI 2 KARENA 88 : 22 = 4 = √4 = 2
88= 2 (3x2x . 3x 1x. 2x 1x)
88= 2(6x+3x+2x)
88=12x+6x+4x
88= 22x
88/22= x
4=x
panjang 3.4= 12 cm
lebar =2.4 = 8cm
tinggi = 1.4 = 4 cm
Semoga membantu
LEBAR = 2
TINGGI = 1
DIK = LUAS PERMUKAAN PERBANDINGAN = ( 3 X 2 ) + ( 2 X 1 ) + ( 3 X 1 ) X 2
= 22
SOL = 88 CM
PANJANG = DIT/DIK X SOL = 3/22 X 88 = 12 : 2 = 6
LEBAR = DIT/DIK X SOL = 2/22 X 88 = 8 : 2 = 4
TINGGI = DIT/DIK X SOL = 1/22 X 88 = 4 : 2 = 2
KET = DIBAGI 2 KARENA 88 : 22 = 4 = √4 = 2