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x+2y-7=0 akan ditemukan 2 titik yaitu x dan y
2x - y = -6
x +2y = 7
2x - y = -6 y ketemu 4, dimasukkan, 2x - 4 = -6
2x +4y = 14 x = 1
__________-
-5y = -20
y = 4
titik sudah ketemu,
tegak lurus dg x+2y-2 = 0 maka nilai m=-1
2y = -x +2
y = -1/2x +1
-1/2 itu nilai m1 maka m2
-1/2.m2 = -1
m2 = 2
dimasukkan dg titik tadi ke rumus (y-y1)=m(x-x1
(y-4)=2(x-1)
y=2x-2+4
y=2x+2
2x-y+2 = 0