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-5=-2x-1
y=-2/-5-1
m=-2/-5=2/5
y-2=2/5 (x+5)
5y-10=2x+10
5y-2x=10+10
5y-2x=20
5y-2x-20=0
semoga berhasil
2x-5y+1=0
melalui titik (-5,2)
M1=2
y-y1 = m (x-x1)
y-2 = 2 (x-(-5))
y-2 = 2(x+5)
y-2 = 2x+10
y = 2x+10+2
y = 2x+12
persamaan lain= 2x-y+12=0