Question

Persamaan garis yang melalui titik ( 5, -6 ) dan tegak lurus dengan garis 3y - 5x + 12 = 0 adalah...

Answer 1

Verified answer

3y - 5x + 12 = 0
5x - 3y - 12 = 0
m = -a / b = -5 / -3 = ⁵/₃

Syarat tegak lurus
m₁ • m₂ = -1
⁵/₃ • m₂ = -1
m₂ = - ⅗

Persamaannya
y - y₁ = m(x - x₁)
y + 6 = - ⅗(x - 5) [× -5]
-5y - 30 = 3(x - 5)
-5y - 30 = 3x- 15
3x + 5y + 15 = 0

Answer 2

3y = 5x - 12 
y = 5/3 x - 4

m = -3/5x
y - y1 = m (x-x1)
y + 6 = -3/5 x + 3 ----
y = - 3/5x - 3