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Mencari gradien garis.
(y1 - y) = m(x1 - x)
(3 - 4) = m(2 - (-1))
-1 = m(3)
m = -1/3
Masukkan ke persamaan garis.
y = mx + c
3 = -1/3(2) + c
3 = -2/3 + c
3 + 2/3 = c
c = 11/3
Jadi persamaan garisnya,
y = -1/3 x + 11/3
3y = -x + 11 " kedua rusa dikali 3 "
x + 3y = 11