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y = (1/2)x - 2
m = 1/2
gradien tegak lrusnya = - 2
y - 1 = -2(x + 1)
y - 1 = - 2x - 2
2x + y + 1 = 0
y = 1/2x - 2
m₁ = 1/2
syarat tegak lurus m₁.m₂ = -1
1/2.m₂ = -1
m₂ = -2
y - y₁ = m₂(x - x₁)
y - 1 = -2(x + 5)
y - 1 = -2x - 10
y = -2x - 10 + 1
y = -2x - 9