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1+2 / -4 -2
3/ -6
krna tegak lurus dibalik 6/3 = 2
y - y1 = m (x-x1)
y+2 = 2(x-2)
y+2 = 2x -4
y= 2x -4 -2
y= 2x -6 atau y-2x+6=0 atau y-2x =-6
smoga membantu :)