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m = -koef x / koef y
= -2/6
= - 1/3
syarat tegak lurus
m1 x m2 = -1
-1/3 x m2 = -1
m2 = -1 ÷ -1/3
m2 = -1 x 3/-1
m2 = 3
y-y1 = m(x-x1)
y - (-2) = 3 ( x - (-4)
y +2 = 3(x+4)
y+2 = 3x + 12
y-3x = 12-12
y - 3x = 10
atau y = 3x + 10
Syarat garis yang tegak lurus m1 × m2 = -1, sehingga m₂ = –1 : -1/3= 3
x₁ = -4
y₁ = -2
m₂ = 3
y - y₁ = m(x - x₁)
y - (-2) = 3(x - (-4))
y + 2 = 3x + 12
y = 3x + 12 - 2
y = 3x + 10
y - 3x = 10