Persamaan garis melalui titik (2,4) dengan persamaan 2X + 3Y = 6 adalah
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3y=-2x+6
y=-2x/3 + 6/3
y=-2x/3 + 3
m1=-2/3
maka:
y-y1=m1(x-x1)
y-4=-2/3(x-2)
3(y-4)=-2(x-2)
3y+12=-2x+4
3y=-2x+4-12
3y=-2x-8
jadi persamaan garis nya adalah 3y=-2x-8