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y = (2/3)x -5/3
m₁ = 2/3
karena tegak lurus maka yg dicari m₂ = -1/m₁
= -3/2
Persamaan garisnya:
y - 0 = (-3/2)(x - 0)
2y = - 3x
3x + 2y = 0
⇔ y = 2/3 x - 5/3
⇔ m = 2/3
syarat tegak lurus m1m2 = -1 ⇒ 2/3 m2 = -1 ⇒ m2 = -3/2
Persamaan garis singgung melalui titik O(0,0) dan m2 = -3/2
y - y1 = -3/2(x-x1)
y - 0 = -3/2(x - 0)
y = -3/2 x atau 2y = -3x atau 3x + 2y = 0