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3y=-2x+6
y=-2/3x+6/3
m=-2/3
tegaklurus
m1.m2=-1
-2/3.m2=-1
m2=-1.-3/2
m2=3/2
y-y1=m(x-x1)
y-3=3/2(x+2)
y=3/2x+6/2+3
----------------------kalikan 2
2y=3x+6+6
2y=3x+12
3x-2y+12=0