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y = -2x+5 ⇒ 2x+y = 5
m =-a/b = -2/1 = -2
syarat tegak lurus ⇒ m₁×m₂ = -1
m₁× (-2) = -1
m₁ = -1/-2
m₁ = 1/2
persamaan garis lurusnya
y-y₁ = m(x-x₁)
2(y-5) = 2[1/2(x-2)]
2y-10 = 1(x-2)
2y-10 = x-2
-x+2y-10+2 = 0
-x+2y-8 = 0
maaf ya kalo salah