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x^2-6x-7
(x-7)(x+1)
kdua ruas dibagi dg 2, didapat :
x²-6x-7 = 0
(x+1)(x-7) = 0
x+1 = 0 dan x-7 = 0
x = -1 x = 7
jadi, akar2nya adalah x = -1 atau x = 7