Question

Persamaan (2+m)x^2 + (2m+4)x + 24=0 mempunyain akar kembar maka nilai n adalah

Answer 1

Mempunyai akar kembar berarti D=0
D = 0
b^2 - 4ac = 0
(2m+4)^2 - 4 x (2+m) x 24 = 0
4m^2 +16m+6 -(192+96m) = 0
4m^2 + 16m+6-192-96m = 0
4m^2 - 80m - 176 = 0
m^2 - 20m - 44m = 0
(m-22) (m+2) = 0
m = 22 atau m= -2

Answer 2

mempunyai akar kembar berarti D=0
D = 0
b^2 - 4ac = 0
(2m+4)^2 - 4 x (2+m) x 24 = 0
4m^2 +16m+6 -(192+96m) = 0
4m^2 + 16m+6-192-96m = 0
4m^2 - 80m - 176 = 0
m^2 - 20m - 44m = 0
(m-22) (m+2) = 0
m = 22 atau m= -2