Question

Tentukan persamaan garis yang tegak lurus 2y+2=-7/4 (x-7) dan melalui titik (-2,-3)

Answer 1

2y+2 = -7/4 (x-7)
2y+2 = -7/4x + 49/4
2y = -7/4x + 12 1/4 - 2
2y = -7/4x + 10 1/4
y = -7/8x + 5 1/8 -----> dari y = mx+c ; maka m = -7/8

Tegak lurus maka
m1 x m2 = -1
-7/8 x m2 = -1
m2 = 8/7

(y-y1) = m (x-x1)
(y-(-3)) = 8/7 (x-(-2))
y+3 = 8/7 (x+2)
y+3 = 8/7x + 16/7
y = 8/7 + 16/7 -3
y = 1 1/7x + 2 2/7 -3
y= 1 1/7x - 5/7