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Q = 55,625 kj/mol
massa metana = 1 gram
mr = 16
mol = massa/Mr = 1/16 = 0,0625 mol
ditayakan Delta H ?
jawaban =
Delta H = -Q/mol
= -55,625/0,0625
= -890 kJ/mol
semoga dapat membantu yah kak.,.,......:)